6b^2+6b=12

Solution for 6b^2+6b=12 equation:

6b^2+6b=12

We move all terms to the left:

6b^2+6b-(12)=0

a = 6; b = 6; c = -12;
Δ = b2-4ac
Δ = 62-4·6·(-12)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-18}{2*6}=\frac{-24}{12}
=-2
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+18}{2*6}=\frac{12}{12}
=1
$